Question
Three identical bodies, each of mass m, are pushed by a force F on a frictionless table as shown in figure.



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Let a be the common acceleration, then F=3maora=F3m Net force on X=ma=m×F3m=F3 Force applied by X on Y=(m+m)a=2m×F3m=2F3 Force applied by Y on Z =ma=m×F3m=F3
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Question Text | Three identical bodies, each of mass m, are pushed by a force F on a frictionless table as shown in figure. |
Answer Type | Text solution:1 |
Upvotes | 151 |