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Suppose, the acceleration due to gravity at the earth's surfac
Concepts of Physics by H. C. Verma
Concepts of Physics

Class 11

HC Verma Part I

Author:
H. C. Verma
Subject:
Physics
1

Chapter 1: Introduction to Physics

35 questions

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2

Chapter 2: Physics and Mathematics

60 questions

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3

Chapter 3: Rest and Motion: Kinematics

88 questions

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4

Chapter 4: The Forces

33 questions

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5

Chapter 5: Newton's Law of Motion

82 questions

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6

Chapter 6: Friction

57 questions

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7

Chapter 7: Circular Motion

63 questions

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8

Chapter 8: Work and Energy

101 questions

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9

Chapter 9: Centre of Mass, Linear momentum Collision

119 questions

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10

Chapter 10: Rotational Mechanics

149 questions

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11

Chapter 11: Gravitation

80 questions

Q1
The acceleration of moon with respect to earth is 0⋅0027 m s  and the acceleration of an apple falling on earth' surface is about 10 m s . Assume that the radius of the moon is one fourth of the earth's radius. If the moon is stopped for an instant and then released, it will fall towards the earth. The acceleration of the moon just before it strikes the earth is.
Q2
Suppose, the acceleration due to gravity at the earth's surface is 10  and at the surface of Mars it is 4⋅0 . A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?
Q3
Consider a planet in some solar system which has a mass double the mass of the earth and density equal to the average density of the earth. An object weighing W on the earth will weight
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12

Chapter 12: Simple Harmonic Motion

111 questions

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13

Chapter 13: Fluid Mechanics

81 questions

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14

Chapter 14: Some Mechanical Properties of Matter

87 questions

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15

Chapter 15: Wave Motion and Waves on a String

96 questions

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16

Chapter 16: Sound Waves

118 questions

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17

Chapter 17: Light Waves

79 questions

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18

Chapter 18: Geometrical optics

123 questions

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19

Chapter 19: Optical Instruments

52 questions

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20

Chapter 20: Dispersion and Spectra

27 questions

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21

Chapter 21: Speed of Light

14 questions

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22

Chapter 22: Photometry

38 questions

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Question
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Solving time: 2 mins

Suppose, the acceleration due to gravity at the earth's surface is 10  and at the surface of Mars it is 4⋅0 . A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?
Acceleration due to gravity

A
A

B
B

C
C

D
D

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Updated on: Feb 8, 2024

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Concepts of Physics (HC Verma Part I)

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Suppose, the acceleration due to gravity at the earth's surface is 10  and at the surface of Mars it is 4⋅0 . A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?
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Text SolutionText solutionverified iconVerified

(c) C

At one point between the Earth and Mars, the gravitational field intensity is zero. So, at that point, the weight of the passenger is zero. The curve C indicates that the weight of the passenger is zero at a point between the Earth and Mars.
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Practice more questions from Concepts of Physics (HC Verma Part I)

Q1
The acceleration of moon with respect to earth is 0⋅0027 m s  and the acceleration of an apple falling on earth' surface is about 10 m s . Assume that the radius of the moon is one fourth of the earth's radius. If the moon is stopped for an instant and then released, it will fall towards the earth. The acceleration of the moon just before it strikes the earth is.
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Suppose, the acceleration due to gravity at the earth's surface is 10  and at the surface of Mars it is 4⋅0 . A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?
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Consider a planet in some solar system which has a mass double the mass of the earth and density equal to the average density of the earth. An object weighing W on the earth will weight
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Practice questions from Concepts of Physics (HC Verma Part I)

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Consider a planet in some solar system which has a mass double the mass of the earth and density equal to the average density of the earth. An object weighing W on the earth will weight
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Concepts of Physics (HC Verma Part I)

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32 → P=3¢i +5tj +4k. ற்றைக் காண்க ன் திசை வேகம் ன் வேகம் முடுக்கம் dt னுகளை மட்டுமே 51 (நேரத்தைச் (நேரத்தைச் 75' dt ள்ளது. = 3 பான னிக்க ற்ற யும் D தரை இதிலிருந்து முடுக்கமானது எதிர்க்குறி Y திசையில் செயல்படும் என அறியலாம். ā=g(-j)=-z பகைவக்ம் சில நேரங்களில் கீழ்நோக்கிய திசையினை நேர்க்குறி y அச்சு என்றும் கருதுவதுண்டு. தடையின்றி தானே செங்குத்தாக கீழ்நோக்கி (விழும் பொருளின் முடுக்கம் ' 'ஐ.இந்நிகழ்வில் நேர்க்குறியாக கருத வேண்டும் (a=g) குறிப்பு 2.10.3 நுண்கணித முறையில் சீரான முடுக்கமடைந்த பொருளின் இயக்கச் சமன்பாடுகள் நேர்கோட்டில் இயங்கும் பொருள் ஒன்றினைக் கருதுக, அதன் சீரான முடுக்கம் '3' என்க. இங்கு சீரான முடுக்கம் என்பது முடுக்கம் ஒரு மாறிலி;அது நேரத்தைச் சாராதது என்று பொருள். நேரம் =0 வினாடியில் பொருளின் திசைவேகம் வினாடியில் பொருளின் dy a= (அல்லது) dv = a dt dt என்க; நேரம் திசைவேகம் V என்க, திசைவேகம் - நேரம் தொடர்பு எந்த ஒரு நேரத்திலும் பொருளின் முடுக்கம் என்பது நேரத்தைப் பொருத்து, திசைவேகத்தின் முதல் வகைக்கெழுவாகும். a:du. dE. குறிப்பு இயக்க நிபந்தனையின்படி (அதாவது நேரம் 0 விலிருந்து வரை மாறும்போது, திசைவேகம் u விலிருந்து V க்கு மாறும்) இரண்டுபக்கமும் தொகைப்படுத்துக.. O jdv = Jadt = a Jdt=[v] =a[t] U v-uat (or) v=u+at v- → (2.7) ((-0) வெரியே எடுக்க முடியாது. இடப்பெயர்ச்சி - நேரம் தொடர்பு (i) பொருளின் திசைவேகம் என்பதுC பொருத்து பொருளின் இடம்பெயர்ச்சிய வகைக் கெழுவாகும். முடுக்கம்:- நேரம் நேரத்தை சார்ர் V= (அல்லத) ds = vdt ds=10 இங்கு v=u+at. de எனவே.ds=(u+at)= t = 0 வினாடிட தொடக்கப்புள்ளியில் உள்ளது இடைவெளியில் பொருளின் எனவும் கருதுக, மேலும் பொ நேரத்தைச் சார்ந்ததல்ல எனக் ds dt [as = udt + [at dt (அல்லது) Sas திசைவேகம் இடப்பெயர்ச்சி (i) பொருளின் முடுக்கமெல் பொருத்தும் திசைவே வகைக்கெழுவாகும். C al dt a= dv dv d dt ds c [ds/dt = v] இங் கடந்த தொகை 1d(y?? 2 ds ds== a= மேலே உள்ள சமக அதாவது திசைவே மாறும்போது துக இடப்பெயர்ச்சி அை
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Modern Physics

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Question Text
Suppose, the acceleration due to gravity at the earth's surface is 10  and at the surface of Mars it is 4⋅0 . A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?
Updated OnFeb 8, 2024
TopicGravitation
SubjectPhysics
ClassClass 11
Answer TypeText solution:1 Video solution: 2
Upvotes286
Avg. Video Duration9 min