Question 18: A student heats some amount of tap water in a calorimeter to a temperature of nearly 50ºC above the room temperature. He then records the temperature of this water as it is cooling down at regular intervals of 2 minutes each. He tabulates his observations as follows :
Time (in minutes) → 0 2 4 6 8 10
Temperature (in ºC) → t₁ t₂ t₃ t₄ t₅ t₆
He is likely to observe that :
(1) (t₁− t₂) > (t₃−t₄) > (t₅ − t₆)
(2) (t₁− t₂) = (t₃−t₄) = (t₅ − t₆)
(3) (t₁− t₂) < (t₃−t₄) < (t₅ − t₆)
(4) (t₁− t₂) < (t₃−t₄) > (t₅ − t₆)

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Question 18: A student heats some amount of tap water in a calorimeter to a temperature of nearly 50ºC above the room temperature. He then records the temperature of this water as it is cooling down at regular intervals of 2 minutes each. He tabulates his observations as follows :

Time (in minutes) →	0	2	4	6	8	10
Temperature (in ºC) →	t₁	t₂	t₃	t₄	t₅	t₆

He is likely to observe that :
(1) (t₁− t₂) > (t₃−t₄) > (t₅ − t₆)
(2) (t₁− t₂) = (t₃−t₄) = (t₅ − t₆)
(3) (t₁− t₂) < (t₃−t₄) < (t₅ − t₆)
(4) (t₁− t₂) < (t₃−t₄) > (t₅ − t₆)

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Text solutionVerified

Answer: When hot water cools down, initially its temperature falls at a higher rate but later the rate of fall of temperature decreases. So, for every two minutes, the temperature difference would be greater in starting and will decrease with time. Therefore, we can say that (t₁− t₂) > (t₃−t₄) > (t₅ − t₆).

Hence, the correct answer is option 1.

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