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A stone is thrown vertically upward with an initial velocity o

Science

Class 9

NCERT

Chapter 1: Matter in Our Surroundings

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Chapter 2: Is Matter Around Us Pure?

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Chapter 3: Atoms and Molecules

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Chapter 4: Structure of the Atom

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Chapter 6: Tissues

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Chapter 7: Diversity in Living Organisms

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Chapter 8: Motion

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Chapter 9: Force and Laws of Motion

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Chapter 10: Work and Energy

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Chapter 11: Sound

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Chapter 12: Why do We Fall Ill?

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Chapter 13: Natural Resourses

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Chapter 14: Improvement in Food Resources

Chapter 15: Gravitation

29 questions

A stone is released from the top of a tower of height

19.6

m. Calculate its final velocity just before touching the ground.

A stone is thrown vertically upward with an initial velocity of

40 m / s

. Taking

g = 10 m / s^{2}

, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth

= 6 \times 1 0^{24}

kg and of the Sun

= 2 \times 1 0^{30} k g

. The average distance between the two is

1.5 \times 1 0^{11}

View all question

Question

Easy

Solving time: 4 mins

A stone is thrown vertically upward with an initial velocity of $40 m / s$ . Taking $g = 10 m / s^{2}$ , find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Views: 6,472 students

Updated on: Aug 2, 2023

Book:

Science (NCERT)

Found 2 tutors discussing this question

Henry Discussed

A stone is thrown vertically upward with an initial velocity of

40 m / s

. Taking

g = 10 m / s^{2}

, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

Initial Velocity

u = 40

Fianl velocity

v = 0

Height,

s = ?

By third equation of motion

v^{2} - u^{2} = 2 g s

0 - 4 0^{2} = - 2 \times 10 \times s

s = \frac{160}{20}

\Rightarrow s = 80 m / s

Toatl distance travelled by stone = upward distance + downwars distance

= 2 \times s = 160 m

Total Diaplacement

= 0

, Since the initial and final point is same.

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Practice more questions from Science (NCERT)

A stone is released from the top of a tower of height

19.6

m. Calculate its final velocity just before touching the ground.

A stone is thrown vertically upward with an initial velocity of

40 m / s

. Taking

g = 10 m / s^{2}

, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth

= 6 \times 1 0^{24}

kg and of the Sun

= 2 \times 1 0^{30} k g

. The average distance between the two is

1.5 \times 1 0^{11}

View all

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Question Text	A stone is thrown vertically upward with an initial velocity of $40 m / s$ . Taking $g = 10 m / s^{2}$ , find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
Updated On	Aug 2, 2023
Topic	Gravitation
Subject	Science
Class	Class 9
Answer Type	Text solution:1 Video solution: 14
Upvotes	1472
Avg. Video Duration	5 min

Object	Density (kg/m³⁾	Volume (m³⁾	Mass (kg)
A B C D	8000 2000	2 4 4	4000 1000 2000

A stone is thrown vertically upward with an initial velocity of $40 m / s$ . Taking $g = 10 m / s^{2}$ , find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Text solutionVerified

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A stone is thrown vertically upward with an initial velocity of 40m/s. Taking g=10m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Text solutionVerified

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A stone is thrown vertically upward with an initial velocity of $40 m / s$ . Taking $g = 10 m / s^{2}$ , find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?