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A stone is allowed to fall from the top of a tower 100m high a

Science

Class 9

NCERT

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Chapter 3: Atoms and Molecules

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Chapter 4: Structure of the Atom

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Chapter 10: Work and Energy

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Chapter 13: Natural Resourses

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Chapter 14: Improvement in Food Resources

Chapter 15: Gravitation

29 questions

Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth

= 6 \times 1 0^{24}

kg and of the Sun

= 2 \times 1 0^{30} k g

. The average distance between the two is

1.5 \times 1 0^{11}

A stone is allowed to fall from the top of a tower

100

m high and at the same time another stone is projected vertically upwards from the ground with a velocity of

25 m / s

. Calculate when and where the two stones will meet.

A ball thrown up vertically returns to the thrower after

6

s. Find

(a)

The velocity with which it was thrown up,

(b)

The maximum height it reaches, and

(c)

Its position after

4

View all question

Question

Medium

Solving time: 4 mins

A stone is allowed to fall from the top of a tower $100$ m high and at the same time another stone is projected vertically upwards from the ground with a velocity of $25 m / s$ . Calculate when and where the two stones will meet.

Views: 7,564 students

Updated on: Feb 7, 2024

Book:

Science (NCERT)

Found 3 tutors discussing this question

Chloe Discussed

A stone is allowed to fall from the top of a tower

100

m high and at the same time another stone is projected vertically upwards from the ground with a velocity of

25 m / s

. Calculate when and where the two stones will meet.

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

Let the stones meet at point A after time

t

For upper stone :

u^{'} = 0

x = 0 + \frac{1}{2} g t^{2}

x = \frac{1}{2} \times 10 \times t^{2}

⟹ x = 5 t^{2}

............(1)

For lower stone :

u = 25

m / s

100 - x = u t - \frac{1}{2} g t^{2}

100 - x = (25) t - \frac{1}{2} \times 10 \times t^{2}

⟹ 100 - x = 25 t - 5 t^{2}

............(2)

Adding (1) and (2), we get

25 t = 100

⟹ t = 4 s

From (1),

x = 5 \times 4^{2}

⟹ x = 80 m

Hence the stone meet at a height of

20

m above the ground after 4 seconds.

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Practice more questions from Science (NCERT)

Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth

= 6 \times 1 0^{24}

kg and of the Sun

= 2 \times 1 0^{30} k g

. The average distance between the two is

1.5 \times 1 0^{11}

A stone is allowed to fall from the top of a tower

100

m high and at the same time another stone is projected vertically upwards from the ground with a velocity of

25 m / s

. Calculate when and where the two stones will meet.

A ball thrown up vertically returns to the thrower after

6

s. Find

(a)

The velocity with which it was thrown up,

(b)

The maximum height it reaches, and

(c)

Its position after

4

View all

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Question Text	A stone is allowed to fall from the top of a tower $100$ m high and at the same time another stone is projected vertically upwards from the ground with a velocity of $25 m / s$ . Calculate when and where the two stones will meet.
Updated On	Feb 7, 2024
Topic	Gravitation
Subject	Science
Class	Class 9
Answer Type	Text solution:1 Video solution: 55
Upvotes	5902
Avg. Video Duration	8 min

A stone is allowed to fall from the top of a tower $100$ m high and at the same time another stone is projected vertically upwards from the ground with a velocity of $25 m / s$ . Calculate when and where the two stones will meet.

Text solutionVerified

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A stone is allowed to fall from the top of a tower 100m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25m/s. Calculate when and where the two stones will meet.

Text solutionVerified

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A stone is allowed to fall from the top of a tower $100$ m high and at the same time another stone is projected vertically upwards from the ground with a velocity of $25 m / s$ . Calculate when and where the two stones will meet.