A hammer weighing 2.5 kg moving with a speed of 1 m s−1 strikes the head of the nail driving it 10 cm into the wall. The acceleration during impact and the impulse imparted to wall will be respectively

Here, m = 2.5 kg, v = 1 m s−1, s = 10 cm = 0.1 m Using, v2=u2+2as or 12=0+2(−a)×0.1 or a=−102=−5ms−2             (negative sign indicates deceleration) We know, Impulse, I=Favg×t=Final linear momentum- Initial linear momentum =m(v−u)=m(v−0)=2.5×1=2.5Ns