A block of metal weighing 2 kg is resting on a frictionless plane. It is struck by a jet releasing water at the rate of 1 kg s−1 and at a speed of5 m s−1. The initial acceleration of the block is

7.5 m s−2

1.25 m s−2

5 m s−2

2.5 m s−2

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A block of metal weighing 2 kg is resting on a frictionless plane. It is struck by a jet releasing water at the rate of 1 kg s−1 and at a speed of5 m s−1. The initial acceleration of the block is

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Text solutionVerified

Here, mb=2kg,mwt=1kgs−1 v=5ms−1,a=? So, Fb=mba and Fw=mwt⋅v Force exerted by water on the block makes it accelerate initially. Thus, Fb=Fw or mba=mwtv Or a=1×52 or a=2.5ms−2

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Question Text	A block of metal weighing 2 kg is resting on a frictionless plane. It is struck by a jet releasing water at the rate of 1 kg s−1 and at a speed of5 m s−1. The initial acceleration of the block is
Answer Type	Text solution:1
Upvotes	150

A block of metal weighing 2 kg is resting on a frictionless plane. It is struck by a jet releasing water at the rate of 1 kg s−1 and at a speed of5 m s−1. The initial acceleration of the block is

Text solutionVerified

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