water (density $ρ$ ) is flowing through the uniform tube of cross-sectional area A with a constant speed v. as shown in the figure. The magnitude of force exerted by the water on the curved corner of the tube is (neglect viscous forces)

3 ρ A v^{2}

2 ρ A v^{2}

2 ρ A v^{2}

\frac{ρ A v ^{2}}{2}

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water (density

ρ

) is flowing through the uniform tube of cross-sectional area A with a constant speed v. as shown in the figure. The magnitude of force exerted by the water on the curved corner of the tube is (neglect viscous forces)

12 mins ago

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Text solutionVerified

FB D

of curved part of tube.

ρ A V^{2} = k F_{res} = k^{2} + k^{2} + 2 k^{2} . \frac{1}{2} = k 3 = 3 ρ A V^{2}

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Question Text	water (density $ρ$ ) is flowing through the uniform tube of cross-sectional area A with a constant speed v. as shown in the figure. The magnitude of force exerted by the water on the curved corner of the tube is (neglect viscous forces)
Answer Type	Text solution:1
Upvotes	150

water (density ρ) is flowing through the uniform tube of cross-sectional area A with a constant speed v. as shown in the figure. The magnitude of force exerted by the water on the curved corner of the tube is (neglect viscous forces)

Text solutionVerified

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water (density $ρ$ ) is flowing through the uniform tube of cross-sectional area A with a constant speed v. as shown in the figure. The magnitude of force exerted by the water on the curved corner of the tube is (neglect viscous forces)