Under the action of a force, a 2kg body moves such that its position x as a function of time is given by x=3t3 where x is in metre and t in second. The work done by the force in the first two seconds is .

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Under the action of a force, a {2}{k}{g} body moves such that

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Under the action of a force, a $2 k g$ body moves such that its position x as a function of time is given by $x = \frac{t ^{3}}{3}$ where x is in metre and t in second. The work done by the force in the first two seconds is .

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Under the action of a force, a

2 k g

body moves such that its position x as a function of time is given by

x = \frac{t ^{3}}{3}

where x is in metre and t in second. The work done by the force in the first two seconds is .

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Question Text	Under the action of a force, a $2 k g$ body moves such that its position x as a function of time is given by $x = \frac{t ^{3}}{3}$ where x is in metre and t in second. The work done by the force in the first two seconds is .
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