Two soap bubbles with radii $r_{1}$ and $r_{2} (r_{1} < r_{2})$ come in contact. Their common surface has a radius of curvature $r$ equal to

(R_{1} + R_{2}) /2

(R_{1} R_{2}) / (R_{1} - R_{2})

(R_{1} R_{2}) / (R_{1} + R_{2})

\int (R_{1} R_{2})

Views: 908 students

Found 3 tutors discussing this question

Mateo Discussed

Two soap bubbles with radii

r_{1}

and

r_{2} (r_{1} < r_{2})

come in contact. Their common surface has a radius of curvature

r

equal to

14 mins ago

Discuss this question LIVE

14 mins ago

Question Text

Two soap bubbles with radii

r_{1}

and

r_{2} (r_{1} < r_{2})

come in contact. Their common surface has a radius of curvature

r

equal to

Filo tutor solution