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Two soap bubbles are blown. In first soap bubble excess pressu

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Two soap bubbles are blown. In first soap bubble excess pressure is 4 times of the second soap bubble. The ratio of the radii of the first and second soap bubble is:

1:4

1:2

2 :1

4:1

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Two soap bubbles are blown. In first soap bubble excess pressure is 4 times of the second soap bubble. The ratio of the radii of the first and second soap bubble is:

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Text solutionVerified

Excess pressure =

Δ P = \frac{4 T}{R}

According to problem,

\frac{Δ P _{A}}{Δ P _{B}} = 4 = \frac{4 T / R _{A}}{4 T / R _{B}} = \frac{R _{B}}{R _{A}}

Therefore,

\frac{R _{A}}{R _{B}} = \frac{1}{4}

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Question Text	Two soap bubbles are blown. In first soap bubble excess pressure is 4 times of the second soap bubble. The ratio of the radii of the first and second soap bubble is:
Answer Type	Text solution:1
Upvotes	150

Two soap bubbles are blown. In first soap bubble excess pressure is 4 times of the second soap bubble. The ratio of the radii of the first and second soap bubble is:

Text solutionVerified

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