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Two radio stations broadcast their program at the same amplitu

Question

Two radio stations broadcast their program at the same amplitude A but at slightly different frequencies $n_{1}$ and $n_{2}$ such that $(n_{1} - n_{2}) = 1 0^{3} Hz$ . A detector receives signals from both the stations simultaneously but only when intensity of signal is greater than $2 A^{2}$ . The time interval between two successive maxima will be :

1 0^{- 1} s

1 0^{- 2} s

1 0^{- 3} s

1 0^{◃} s

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Two radio stations broadcast their program at the same amplitude A but at slightly different frequencies

n_{1}

and

n_{2}

such that

(n_{1} - n_{2}) = 1 0^{3} Hz

. A detector receives signals from both the stations simultaneously but only when intensity of signal is greater than

2 A^{2}

. The time interval between two successive maxima will be :

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Text solutionVerified

Given :

(n_{1} - n_{2}) = 1 0^{3} H z = b e a t s

Intensity will be

2 A^{2}

when amplitude is

2 A

.
Amplitude will be

2 A

when the two signals have resonance, and time difference between two successive resonance is inverse of beats.
So,

t = \frac{1}{B e a t}

= \frac{1}{1 0 ^{3}} = 1 0^{- 3} s

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Question Text	Two radio stations broadcast their program at the same amplitude A but at slightly different frequencies $n_{1}$ and $n_{2}$ such that $(n_{1} - n_{2}) = 1 0^{3} Hz$ . A detector receives signals from both the stations simultaneously but only when intensity of signal is greater than $2 A^{2}$ . The time interval between two successive maxima will be :
Answer Type	Text solution:1
Upvotes	150