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Two loudspeakers L_1 and L_2 driven by a common oscillator and

Question

Two loudspeakers $L_{1}$ and $L_{2}$ driven by a common oscillator and amplifier, are arranged as shown. The frequency of the oscillator is gradually increased from zero and the detector at $D$ records a series of maxima and minima. If the speed of sound is $330 m s^{- 1}$ then the frequency at which the first maximum is observed is :

165 Hz

330 Hz

495 Hz

660 Hz

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Sebastian Discussed

Two loudspeakers

L_{1}

and

L_{2}

driven by a common oscillator and amplifier, are arranged as shown. The frequency of the oscillator is gradually increased from zero and the detector at

D

records a series of maxima and minima. If the speed of sound is

330 m s^{- 1}

then the frequency at which the first maximum is observed is :

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Text solutionVerified

Path difference

Δ x = 9^{2} + 4 0^{2} - 40 = 1

m
Hence phase change =

δ = \frac{2 π}{λ} Δ x = \frac{2 π}{λ}

For the first maximum

δ = \frac{2 π}{λ} = 2 π

Hence

λ = 1 m

Frequency

= ν = \frac{v}{λ} = 330 Hz

Ans: B

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Question Text	Two loudspeakers $L_{1}$ and $L_{2}$ driven by a common oscillator and amplifier, are arranged as shown. The frequency of the oscillator is gradually increased from zero and the detector at $D$ records a series of maxima and minima. If the speed of sound is $330 m s^{- 1}$ then the frequency at which the first maximum is observed is :
Answer Type	Text solution:1
Upvotes	150

Text solutionVerified

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