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two equal drops of water each of radius r are falling through

Question

two equal drops of water each of radius $r$ are falling through air with a steady velocity $8 c m / s$ . the two drops combine to form a big drop. The terminal velocity of big drop will be:

8 (2)^{\frac{2}{3}} c m / s

16 (2)^{\frac{2}{3}} c m

4 (2)^{\frac{2}{3}} c m

32 c m / s

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Evelyn Discussed

two equal drops of water each of radius

r

are falling through air with a steady velocity

8 c m / s

. the two drops combine to form a big drop. The terminal velocity of big drop will be:

9 mins ago

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9 mins ago

Text solutionVerified

V = \frac{m g}{6 πh r θ}

S = \frac{m g}{6 πh r v}

2 [\frac{4}{3} π r^{3}] g = \frac{4}{3} π R^{3} g

R = 2^{\frac{9}{3}} r

V_{1} = \frac{2 m g}{6 πh R}

V_{1} = \frac{2 m g}{6 πh r}

= 2 \times 8

V_{1} = 8 \times (2)^{2/3} c m / sec

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Question Text	two equal drops of water each of radius $r$ are falling through air with a steady velocity $8 c m / s$ . the two drops combine to form a big drop. The terminal velocity of big drop will be:
Answer Type	Text solution:1
Upvotes	150