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Terminal velocity

Two drops of the same radius are falling through air with a st

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Two drops of the same radius are falling through air with a steady velocity of 5 cm/s. If the two drops coalesce, the terminal velocity would be

10 c m / s

2.5 c m / s

5 (4)^{1/3} c m / s

5 (3)^{1/3} c m / s

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Updated on: Aug 23, 2023

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Two drops of the same radius are falling through air with a steady velocity of 5 cm/s. If the two drops coalesce, the terminal velocity would be

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Text solutionVerified

R

is radius of bigger drop formed, then

\frac{4}{3} π R^{3} = 2 \times \frac{4}{3} π r^{3} or R = 2^{1/3} r

As v_{0} \propto r^{2}

∴ \frac{v _{01}}{v _{0}} = \frac{R ^{2}}{r ^{2}} = \frac{( 2 ^{1/3} ) ^{2}}{r ^{2}} = 2^{2/3}

or v_{01} = v_{0} 2^{2/3} = 5 (4)^{1/3} c m / s

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Question Text	Two drops of the same radius are falling through air with a steady velocity of 5 cm/s. If the two drops coalesce, the terminal velocity would be
Updated On	Aug 23, 2023
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 3
Upvotes	467
Avg. Video Duration	5 min

Two drops of the same radius are falling through air with a steady velocity of 5 cm/s. If the two drops coalesce, the terminal velocity would be

Text solutionVerified

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Two drops of the same radius are falling through air with a steady velocity of 5 cm/s. If the two drops coalesce, the terminal velocity would be

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