The work done in increasing the size of a rectangular soap film with dimensions 8 cm×3.75 cm to 10 cm×6 cm is 2×10−4J. The surface tension of the film in N/m is

Name: Video solution 1: The work done in increasing the size of a rectangular soap film with dimensions 8 cm×3.75 cm to 10 cm×6 cm is 2×10−4J. The surface tension of the film in N/m is
Uploaded: 2023-04-16T12:26:26.000Z
Duration: 4 min
Description: Video solution 1: The work done in increasing the size of a rectangular soap film with dimensions 8 cm×3.75 cm to 10 cm×6 cm is 2×10−4J. The surface tension of the film in N/m is

ΔA=2[10×6−8×3.75]=60 cm2Δ⋃=2×10−4 J2×10−4=60×10−4×T3.3×10−2 N/m=T

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Mechanical Properties of Fluids

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The work done in increasing the size of a rectangular soap fil

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The work done in increasing the size of a rectangular soap film with dimensions $8 c m \times 3.75 c m$ to $10 c m \times 6 c m$ is $2 \times 10^{- 4} J$ . The surface tension of the film in $N / m$ is

1.65 \times 10^{- 2}

3.3 \times 10^{- 2}

6.6 \times 10^{- 2}

8.25 \times 10^{- 2}

Views: 5,932 students

Updated on: Apr 16, 2023

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The work done in increasing the size of a rectangular soap film with dimensions

8 c m \times 3.75 c m

10 c m \times 6 c m

2 \times 10^{- 4} J

. The surface tension of the film in

N / m

5 mins ago

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5 mins ago

Text solutionVerified

Δ A = 2 [10 \times 6 - 8 \times 3.75]

= 60 cm^{2}

Δ ⋃ = 2 \times 1 0^{- 4} J

2 \times 1 0^{- 4} = 60 \times 1 0^{- 4} \times T

3.3 \times 1 0^{- 2} N / m = T

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Question Text	The work done in increasing the size of a rectangular soap film with dimensions $8 c m \times 3.75 c m$ to $10 c m \times 6 c m$ is $2 \times 10^{- 4} J$ . The surface tension of the film in $N / m$ is
Updated On	Apr 16, 2023
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	204
Avg. Video Duration	4 min

The work done in increasing the size of a rectangular soap film with dimensions $8 c m \times 3.75 c m$ to $10 c m \times 6 c m$ is $2 \times 10^{- 4} J$ . The surface tension of the film in $N / m$ is

Text solutionVerified

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The work done in increasing the size of a rectangular soap film with dimensions 8 cm×3.75 cm to 10 cm×6 cm is 2×10−4J. The surface tension of the film in N/m is

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The work done in increasing the size of a rectangular soap film with dimensions $8 c m \times 3.75 c m$ to $10 c m \times 6 c m$ is $2 \times 10^{- 4} J$ . The surface tension of the film in $N / m$ is