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The ratio of power required to move the plate at the speed 1 m

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The ratio of power required to move the plate at the speed $1 m / s$ for the two cases is

1

8/9

1/3

4/9

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The ratio of power required to move the plate at the speed

1 m / s

for the two cases is

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Text solutionVerified

Ratio of power required for the two cases is:

\frac{P _{1}}{P _{2}} = \frac{F _{1} . v _{1}}{F _{2} . v _{2}}

\Rightarrow \frac{P _{1}}{P _{2}} = \frac{( 0.8 \times 0.01 \times \frac{1}{0.03} + 0.8 \times 0.01 \times \frac{1}{0.03} ) .1}{( 0.8 \times 0.01 \times \frac{1}{0.02} + 0.8 \times 0.01 \times \frac{1}{0.04} ) .1}

\Rightarrow \frac{P _{1}}{P _{2}} = \frac{\frac{2}{0.03}}{( \frac{1}{0.02} + \frac{1}{0.04} )} = \frac{\frac{2}{0.03}}{( \frac{0.06}{0.02 \times 0.04} )} = \frac{2}{0.03} \times \frac{0.02 \times 0.04}{0.06} = \frac{8}{9}

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Question Text	The ratio of power required to move the plate at the speed $1 m / s$ for the two cases is
Answer Type	Text solution:1
Upvotes	150