The nuclear radius of 8O16 is 3×10−15. If an atomic mass unit is 1.67×10−27kg, then the nuclear density is approximately

[b] For nucleus of 8O16 Mass =(16)(1.67×10−27)kg Volume =43πR3 =43π(3×10−15)3m3=36π×10−45m3 Density =massvolume=16×1.67×10−27kg36π×10−45m3 =2.35×1017kgm−3