The nuclear fusion reaction2H2→2He4+Energy , is proposed to be used for the production of industrial power. Assuming the efficiency of process for production of power is 20%, find the ass of the deuterium required approximately for a duration of 1 year. Given mass of 1H2 nucleus = 2.0141 a.m.u and mass of2He4 nuclei = 4.0026 a.m.u and 1 a.m.u. = 31 MeV

Question

The nuclear fusion reaction2H2→2He4+Energy , is proposed to be used for the production of industrial power. Assuming the efficiency of process for production of power is 20%, find the ass of the deuterium required approximately for a duration of 1 year. Given mass of 1H2 nucleus = 2.0141 a.m.u and mass of2He4 nuclei = 4.0026 a.m.u and 1 a.m.u. = 31 MeV

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[b] Mass defect Δm=2×2.014−4.0026=0.0256a.m.u. Energy released when two 1H2 nuclei fuse =0.0256×931=23.8 MeV Total energy required to be produced by nuclear reaction in 1 year =2500×106×3.15×107=7.88×1016J No. of nuclei of 1H2 required =7.88×1016J23.8×1.6×10−13×2=4.14×1028 Mass of Deuterium required =4.14×10286.02×1023×2×10−3kg=138kg

Question Text	The nuclear fusion reaction2H2→2He4+Energy , is proposed to be used for the production of industrial power. Assuming the efficiency of process for production of power is 20%, find the ass of the deuterium required approximately for a duration of 1 year. Given mass of 1H2 nucleus = 2.0141 a.m.u and mass of2He4 nuclei = 4.0026 a.m.u and 1 a.m.u. = 31 MeV
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