The maximum amplitude for an amplitude modulated wave is found to be $12 V$ while the minimum amplitude is found to be $3 V$ . The modulation index is $0.6 x$ where $x$ is____________

ion. This results in the formation of a hydrogen atoms in the first excited state and a photon is released. Find the frequency of the emitted photon.

A free electron of

2.6 eV

energy collides with

a H^{+}

(h = 6.6 \times 1 0^{- 34} J s)

$1.45 \times 1 0^{16} MHz$
$1.45 \times 1 0^{9} MHz$
$9.0 \times 1 0^{27} MHz$
$0.19 \times 1 0^{15} MHz$

Topic:

Atoms

Exam:

JEE Mains 2021 Aug 31 Shift 2

View 10 solutions

A series L C R circuit driven by 300 V at frequency of 50 Hz contains a resistance R =3 k

Ω

, an inductor of inductive reactance

X_{L} = 250 π Ω

and an unknown capacitor. The value of capacitance to maximize the average power should be: (take

π^{2} = 10

)

$4 μ F$
$400 μ F$
$40 μ F$
$25 μ F$

Topic:

Alternating Current

Exam:

JEE Mains 2021 Aug 26 Shift 1

View 2 solutions

light beam is described by

E = 800 sin ω (t - \frac{x}{c})

. An electron is allowed to move normal to the propagation of light beam with a speed of

3 \times 1 0^{7}

. What is the maximum magnetic force exerted on the electron?

$1.28 \times 1 0^{- 21} N$
$1.28 \times 1 0^{- 18} N$
$12.8 \times 1 0^{- 18} N$
$12.8 \times 1 0^{- 17} N$

Topic:

Electromagnetic Induction

Exam:

JEE Mains 2021 Aug 26 Shift 2

View 3 solutions

In the reported figure, two bodies

A

B

of masses

200 g

are attached with the system of springs. Springs are kept in a stretched position with some extension when the system is released. The horizontal surface is assumed to be frictionless. The angular frequency will be

800 g

rad / s

when

k = 20

N / m .

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

Exam:

JEE Mains 2021 July 25 Shift 1

View 4 solutions

Practice questions from Semiconductor Electronics: Materials, Devices and Simple Circuits in the same exam

In the logic circuit shown in the figure, if input A and B are 0 to 1 respectively, the output at Y would be 'x'. The value of x is .

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

Exam:

JEE Mains 2021 Mar 16 Shift 1

View 2 solutions

The energy band gap is maximum in
(a) metals
(b) superconductors
(c) insulators
(d) semiconductors

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2002

View 2 solutions

For the circuit shown below, calculate the value of I_{2} :

$0.15 A$
$25 mA$
$0.05 A$
$0.1 A$

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

Exam:

JEE Mains 2021 July 20 Shift 1

View 4 solutions

A telephonic communication service is working at carrier frequency of

10 GHz

. Only

10%

of it is utilised for transmission. How many telephonic channels can be transmitted simultaneously, if each channel requires a bandwidth of

5 kHz

?
(a)

2 \times 1 0^{3}

(b)

2 \times 1 0^{4}

(c)

2 \times 1 0^{5}

(d)

2 \times 1 0^{6}

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2018

View 2 solutions

Practice more questions from Semiconductor Electronics: Materials, Devices and Simple Circuits

The antenna current of an AM transmitter is

Hard

8 A

when only the carrier is sent, but it increases to

8.93 A

when the carrier is modulated by single sine wave. Find the percentage modulation.

$60.1%$
$70.1%$
$80.1%$
$50.1%$

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

View 3 solutions

When only carrier is transmitted antenna current observed is

8 A

. When it is modulated with

500 Hz

sine wave antenna current becomes

9.6

A. Find % modulation.

$80%$
$20%$
$94.26%$
$83.76%$

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

Book:

Master Resource Book in JEE Main Physics (Arihant)

View solution

दर्शाए गए तर्क परिपथ के लिए, सत्यमान सारणी है :

$A 0011 B 0101 Y 0111$
$A 0011 B 0101 Y 1110$
$A 0011 B 0101 Y 1000$
$A 0011 B 0101 Y 0001$

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

View 4 solutions

A common emitter amplifier has a voltage gain of 50 , an input impedance of

100Ω

and an output impedance of

200Ω

. The power gain of the amplifier is

100
500
1000
1250

Topic:

Semiconductor Electronics: Materials, Devices and Simple Circuits

View 5 solutions

Practice questions on similar concepts asked by Filo students

A rubber band that is stretched more than a tiny bit is not a very good approximation to a harmonic oscillator. Suppose its potential is given by the equation: V(x) = kx^2 + ax^3 + bx^4 where a and b are both small positive constants.

Sketch the potential for k = 1, a = 1/2, and b = 1/8.
Show that the only stable equilibrium point is still at x = 0.
Find the frequency of small oscillations about this point.
Find the corrections to frequency and the apparent equilibrium point related to nonlinear effects when the oscillations are not so small.

Topic:

Physics

View solution

2 Pradeep's Fundamental Physics (XII) vor 5. ELECTRIC FIELD INTENSITY DUE TO A THIN INFINITE PLANE SHEET OF CHARGR Consider a thin, infinite plane sheet of charge. Let

σ

be the surface density of charge on the sheet

(i_{,}

ge/area). We have to calculate electric field intensity

E

at any point

P

, (at a perpendicular distance), the sheet. From symmetry, we find that

E

on either side of the sheet must be perpendicular to the plane of the having same magnitude at all points equidistant from the sheet. Let us imagine a cylinder of cross-sectional

l s

around

P

and length

2 r

, piercing through leet. At the two cylindrical edges

P

are parallel to each other, 46. electric flux over these edges

Q

, d outward normal

\overset{n}{^}

= 2 E \cdot \overset{n}{^} d s = 2 E d s

n the curved surface of the cylinder,

E

Topic:

Electrostats

View solution

A capacitor is a system of two conductors separated by an insulator. The two conductors have equal and opposite charges with a potential difference between them. The capacitance of a capacitor depends on the geometrical configuration (shape, size and separation) of the system and also on the nature of the insulator separating the two conductors. They are used to store charges. Like resistors, capacitors can be arranged in series or parallel or a combination of both to obtain desired value of capacitance.

(i) Find the equivalent capacitance between points $A$ and $B$ in the given diagram.
(ii) A dielectric slab is inserted between the plates of a parallel plate capacitor. The electric field between the plates decreases. Explain.
(iii) A capacitor A of capacitance $C$ , having charge $Q$ is connected across another uncharged capacitor B of capacitance 2 C. Find an expression for (a) the potential difference across the combination and (b) the charge lost by capacitor $A$ .
(iii) Two slabs of dielectric constants $2 K$ and $K$ fill the space between the plates of a parallel plate capacitor of plate area $A$ and plate separation $d$ as shown in figure. Find an expression for capacitance of the system.

Topic:

Electrostats

View solution