Class 12

Physics

Mechanics

Gravitation

The height a which the weight of a body becomes $1/16th$ its weight on the surface of earth (radius $R$) is

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A rocket is fired from the earth towards the sun. At what distance from the earths centre is the gravitational force on the rocket zero? Mass of the sun = $2×10_{30}kg$, mass of the earth = $6×10_{24}kg$. Neglect the effect of other planets etc. (orbital radius = $1.5×10_{11}m$).

Buoyant force exerted by a fluid on a given body is :

The upward force acting on the body immersed in a fluid is called :

The satellite of mass m revolving in a circular orbit of radius r around the earth has kinetic energy E. then, its angular momentum will be

Assertion :A block of wood is floating in a pond of water and its apparent weigth is zero. Reason :The weight of water displaced (buoyant force) acting vertically upwards is just equal to the weight of the body which acts vertically downwards.

The escape velocity of a sphere of mass m is given by (G= univesal gravitational constant, $M_{e}=$ mass of the earth and $R_{e}=$ radius of the earth)

What will be the formula of the mass in terms of g,R and G ? (R = radius of the earth)

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