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The half life of radioactive Radon is 3.8 days. The time at th

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Medium

Solving time: 3 mins

The half life of radioactive Radon is $3.8$ days. The time at the end of which $1/20^{t h}$ of the Radon sample will remain undecayed is (Given $lo g_{10} e = 0.4343$ )

3.8

days

16.5

days

33 days

76 days

Views: 5,888 students

Updated on: Mar 22, 2023

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Mila Discussed

The half life of radioactive Radon is

3.8

days. The time at the end of which

1/20^{t h}

of the Radon sample will remain undecayed is (Given

lo g_{10} e = 0.4343

)

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

t_{1/2} = 3.8 d a y

∴ λ = \frac{0.693}{t _{1/2}} = \frac{0.693}{3.8} = 0.182

If the initial number of atom is

a = A_{0}

then after time

t

the number of atoms is

a /20 = A .

t = \frac{2.303}{λ} lo g \frac{A _{0}}{A} = \frac{2.303}{0.182} lo g \frac{a}{a /20}

= \frac{2.303}{0.182} lo g 20 = 16.46 d a ys

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Question Text	The half life of radioactive Radon is $3.8$ days. The time at the end of which $1/20^{t h}$ of the Radon sample will remain undecayed is (Given $lo g_{10} e = 0.4343$ )
Updated On	Mar 22, 2023
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 3
Upvotes	309
Avg. Video Duration	11 min

The half life of radioactive Radon is $3.8$ days. The time at the end of which $1/20^{t h}$ of the Radon sample will remain undecayed is (Given $lo g_{10} e = 0.4343$ )

Text solutionVerified

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The half life of radioactive Radon is $3.8$ days. The time at the end of which $1/20^{t h}$ of the Radon sample will remain undecayed is (Given $lo g_{10} e = 0.4343$ )