The half-life of a sample of a radioactive substance is 1 hour. If 8×1010 atoms are present at t=0, then the number of atoms decayed in the duration t=2 hour to t=4 hour will be

2×1010

1.5×1010

Zero

Infinity

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The half-life of a sample of a radioactive substance is 1 hour. If 8×1010 atoms are present at t=0, then the number of atoms decayed in the duration t=2 hour to t=4 hour will be

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Text solutionVerified

[b]N=N0(12)tT1l2

N o o f a \to m s a t t = 2 h r, N 1 = 8 \times 1010 (12) 21 = 2 \times 1010

No. of atoms at t = 4hr, N2=8×1010(12)41=12×1010

∴ N ⊙ o f a \to m s d e c a y e d \in g i v e n d u r a t i o n

=(2−12)×1010=1.5×1010

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Question Text	The half-life of a sample of a radioactive substance is 1 hour. If 8×1010 atoms are present at t=0, then the number of atoms decayed in the duration t=2 hour to t=4 hour will be
Answer Type	Text solution:1
Upvotes	151

The half-life of a sample of a radioactive substance is 1 hour. If 8×1010 atoms are present at t=0, then the number of atoms decayed in the duration t=2 hour to t=4 hour will be

Text solutionVerified

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