The bob of a pendulum of mass 8μg carries an electric charge of 39.2×10−10 coulomb in an electric field of 20×103 volt/meter and it is at rest. The angle made by the pendulum with the vertical will be

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The bob of a pendulum of mass {8}{g} carries an electric charg

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The bob of a pendulum of mass $8 μ g$ carries an electric charge of $39.2 \times 10^{- 10}$ coulomb in an electric field of $20 \times 10^{3}$ volt/meter and it is at rest. The angle made by the pendulum with the vertical will be

27^{\circ}

45^{\circ}

87^{\circ}

127^{\circ}

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The bob of a pendulum of mass

8 μ g

carries an electric charge of

39.2 \times 10^{- 10}

coulomb in an electric field of

20 \times 10^{3}

volt/meter and it is at rest. The angle made by the pendulum with the vertical will be

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Question Text	The bob of a pendulum of mass $8 μ g$ carries an electric charge of $39.2 \times 10^{- 10}$ coulomb in an electric field of $20 \times 10^{3}$ volt/meter and it is at rest. The angle made by the pendulum with the vertical will be
Answer Type	Video solution: 1
Upvotes	150