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The binding energy of deuteron (21H) is 1.15 A MeV per nucleon
Question

The binding energy of deuteron (21H) is 1.15 A MeV per nucleon and an alpha particle (42He)has a binding energy of 7.1 MeV per nucleon. Then in the reaction 21He+21He→22He+Q the energy released Q is:

A
5.95 MeV

B
26.1 MeV

C
23.8 MeV

D
289.4 MeV

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The binding energy of deuteron (21H) is 1.15 A MeV per nucleon and an alpha particle (42He)has a binding energy of 7.1 MeV per nucleon. Then in the reaction 21He+21He→22He+Q the energy released Q is:
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[c] Given,  1H2+1H2→2H4+Q The total binding energy of the deutrons =4×1.15=4.60MeV The total binding energy of alpha particle =4×7.1=28.4MeV The energy released in the process =28.4−4.60=23.8MeV.
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Question Text
The binding energy of deuteron (21H) is 1.15 A MeV per nucleon and an alpha particle (42He)has a binding energy of 7.1 MeV per nucleon. Then in the reaction 21He+21He→22He+Q the energy released Q is:
Answer TypeText solution:1
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