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Physics Part-I

Gravitation

Suppose there existed a planet that went around the sun twice

Physics Part-I

Class 11

NCERT

Chapter 1: Physical World

16 questions

Chapter 2: Units and Measurements

51 questions

Chapter 3: Motion in Straight Line

50 questions

Chapter 4: Motion in a Plane

43 questions

Chapter 5: Laws of motion

52 questions

Chapter 6: Work, Energy and Power

41 questions

Chapter 7: System of Particles and Rotational Motion

45 questions

Chapter 8: Gravitation

33 questions

Choose the correct alternative :
(a) Acceleration due to gravity increases/decreases with increasing altitude.
(b) Acceleration due to gravity increases/decreases with increasing depth (assume the earth to be a sphere of uniform density).
(c) Acceleration due to gravity is independent of mass of the earth/mass of the body.
(d) The formula

- G M m (1/ r_{2} - 1/ r_{1})

is more/less accurate than the formula

m g (r_{2} - r_{1})

for the difference of potential energy between two points

r_{2}

and

r_{1}

distance away from the center of the earth.

Suppose there existed a planet that went around the sun twice as fast as the earth.What would be its orbital size as compared to that of the earth ?

Io, one of the satellites of Jupiter has an orbital period of 1.769 days and the radius of the orbit is

4.22 \times 1 0^{8} m

. Show that the mass of Jupiter is about one-thousandth that of the sun.

View all question

Question

Easy

Solving time: 2 mins

Suppose there existed a planet that went around the sun twice as fast as the earth.What would be its orbital size as compared to that of the earth ?

Views: 6,634 students

Updated on: Sep 26, 2023

Book:

Physics Part-I (NCERT)

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Suppose there existed a planet that went around the sun twice as fast as the earth.What would be its orbital size as compared to that of the earth ?

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Text solutionVerified

Time taken by the Earth to complete one revolution around the Sun,

T_{e} = 1

year

Time taken by the planet to complete one revolution around the Sun,

T_{P} = \frac{1}{2} T_{e} = \frac{1}{2} ye a r

Orbital radius of the planet = Rp

From Kepler’s third law of planetary motion, we can write:

(\frac{R _{P}}{R _{e}})^{3} = (\frac{T _{P}}{T _{e}})^{2}

(\frac{R _{P}}{R _{e}}) = (\frac{T _{P}}{T _{e}})^{2/3}

= 0. 5^{(2/3)} = 0.63

Hence, the orbital radius of the planet will be 0.63 times of the Earth.

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Practice more questions from Physics Part-I (NCERT)

- G M m (1/ r_{2} - 1/ r_{1})

is more/less accurate than the formula

m g (r_{2} - r_{1})

for the difference of potential energy between two points

r_{2}

and

r_{1}

distance away from the center of the earth.

Suppose there existed a planet that went around the sun twice as fast as the earth.What would be its orbital size as compared to that of the earth ?

Io, one of the satellites of Jupiter has an orbital period of 1.769 days and the radius of the orbit is

4.22 \times 1 0^{8} m

. Show that the mass of Jupiter is about one-thousandth that of the sun.

View all

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Question Text	Suppose there existed a planet that went around the sun twice as fast as the earth.What would be its orbital size as compared to that of the earth ?
Updated On	Sep 26, 2023
Topic	Gravitation
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 10
Upvotes	920
Avg. Video Duration	5 min

Suppose there existed a planet that went around the sun twice as fast as the earth.What would be its orbital size as compared to that of the earth ?

Text solutionVerified

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Suppose there existed a planet that went around the sun twice as fast as the earth.What would be its orbital size as compared to that of the earth ?

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