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Starting with a sample of pure { }^{66} C u, 7 / 8 of it decay

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Solving time: 2 mins

Starting with a sample of pure $^{66} C u, 7/8$ of it decays into $Zn$ in $15 min$ . The corresponding half-life is

Name: Video solution 1: Starting with a sample of pure 66Cu,7/8 of it decays into Zn in 15 min. The corresponding half-life is
Uploaded: 2023-02-17T11:58:17.000Z
Duration: 15 min
Description: Video solution 1: Starting with a sample of pure 66Cu,7/8 of it decays into Zn in 15 min. The corresponding half-life is

10 min

15 min

5 min

7 \frac{1}{2} min

Views: 5,615 students

Updated on: Feb 17, 2023

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Starting with a sample of pure

^{66} C u, 7/8

of it decays into

Zn

15 min

. The corresponding half-life is

15 mins ago

Discuss this question LIVE

15 mins ago

Text solutionVerified

N = N_{0} (1 - e^{- λ t})

\Rightarrow \frac{N _{0} - N}{N _{0}} = e^{- λ t}

∴ \frac{1}{8} = e^{- λ t}

\Rightarrow 8 = e^{λ t}

\Rightarrow 3 ln 2 = λ t

\Rightarrow λ = \frac{3 \times 0.693}{15}

Half-life period,

t_{1/2} = \frac{0.693}{3 \times 0.693} \times 15

t_{1/2} = 5 min

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Question Text	Starting with a sample of pure $^{66} C u, 7/8$ of it decays into $Zn$ in $15 min$ . The corresponding half-life is
Updated On	Feb 17, 2023
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 1
Upvotes	195
Avg. Video Duration	15 min

Starting with a sample of pure $^{66} C u, 7/8$ of it decays into $Zn$ in $15 min$ . The corresponding half-life is

Text solutionVerified

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