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Moment of inertia

Let the moment of inertia of a hollow cylinder of length 30 {~

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Let the moment of inertia of a hollow cylinder of length $30 cm$ (inner radius $10 cm$ and outer radius $20 cm$ ) about its axis be $I$ . The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also $I$ , is
(a) $16 cm$
(b) $14 cm$
(c) $12 cm$
(d) $18 cm$

Name: Video solution 1: Let the moment of inertia of a hollow cylinder of length 30 cm (inner radius 10 cm and outer radius 20 cm ) about its axis be I. The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also I, is(a) 16 cm(b) 14 cm(c) 12 cm(d) 18 cm
Uploaded: 2022-10-25T11:54:08.000Z
Duration: 7 min
Description: Video solution 1: Let the moment of inertia of a hollow cylinder of length 30 cm (inner radius 10 cm and outer radius 20 cm ) about its axis be I. The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also I, is(a) 16 cm(b) 14 cm(c) 12 cm(d) 18 cm

Views: 5,156 students

Updated on: Oct 25, 2022

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2019

Found 7 tutors discussing this question

William Discussed

Let the moment of inertia of a hollow cylinder of length

30 cm

(inner radius

10 cm

and outer radius

20 cm

) about its axis be

I

. The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also

I

, is
(a)

16 cm

(b)

14 cm

(c)

12 cm

(d)

18 cm

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

Exp. (a)
Moment of inertia of hollow cylinder about its axis is

I_{1} = \frac{M}{2} (R_{1}^{2} + R_{2}^{2})

where,

R_{1} =

inner radius and

R_{2} =

outer radius.
Moment of inertia of thin hollow cylinder of radius

R

about its axis is.

I_{2} = M R^{2}

Given,

I_{1} = I_{2}

and both cylinders have same mass

(M)

. So, we have

\frac{M}{2} (R_{1}^{2} + R_{2}^{2}) = M R^{2}

(1 0^{2} + 2 0^{2}) /2 = R^{2}

R^{2} = 250 = 15.8

R = 16 cm

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Question Text	Let the moment of inertia of a hollow cylinder of length $30 cm$ (inner radius $10 cm$ and outer radius $20 cm$ ) about its axis be $I$ . The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also $I$ , is (a) $16 cm$ (b) $14 cm$ (c) $12 cm$ (d) $18 cm$
Updated On	Oct 25, 2022
Topic	System of Particles and Rotational Motion
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	110
Avg. Video Duration	7 min

Let the moment of inertia of a hollow cylinder of length $30 cm$ (inner radius $10 cm$ and outer radius $20 cm$ ) about its axis be $I$ . The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also $I$ , is
(a) $16 cm$
(b) $14 cm$
(c) $12 cm$
(d) $18 cm$

Text solutionVerified

Filo tutor solutions (1)

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Let the moment of inertia of a hollow cylinder of length 30 cm (inner radius 10 cm and outer radius 20 cm ) about its axis be I. The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also I, is(a) 16 cm(b) 14 cm(c) 12 cm(d) 18 cm

Text solutionVerified

Filo tutor solutions (1)

Questions from JEE Mains 2019 - PYQs

Practice questions from Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Practice questions from System of Particles and Rotational Motion in the same exam

Practice more questions from System of Particles and Rotational Motion

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Let the moment of inertia of a hollow cylinder of length $30 cm$ (inner radius $10 cm$ and outer radius $20 cm$ ) about its axis be $I$ . The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also $I$ , is
(a) $16 cm$
(b) $14 cm$
(c) $12 cm$
(d) $18 cm$