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Let 123√sec be the coefficient of friction between blocks of mass m and M. The pulleys are frictionless and strings are massless. Acceleration of mass m is
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From the constraint net acceleration m=a2+(2a)2−−−−−−−−√=5√amg=T−μN=2ma 2T=(M+m)a
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Question Text | Let 123√sec be the coefficient of friction between blocks of mass m and M. The pulleys are frictionless and strings are massless. Acceleration of mass m is |
Answer Type | Text solution:1 |
Upvotes | 150 |