In the reaction 21H+31H→42He+10n. If the tending energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is

c+a−b

c−a−b

a+b+c

a+b−c

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In the reaction 21H+31H→42He+10n. If the tending energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is

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Text solutionVerified

[b] During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released = c (a + b) = c a b

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Question Text	In the reaction 21H+31H→42He+10n. If the tending energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is
Answer Type	Text solution:1
Upvotes	150

In the reaction 21H+31H→42He+10n. If the tending energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is

Text solutionVerified

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