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In Millikan oil drop experiment a charged drop falls with a te

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In Millikan oil drop experiment a charged drop falls with a terminal velocity $V$ . If an electric field $E$ is applied vertically upwards it moves with terminal velocity $2 V$ in upward direction. If electric field reduces to $E /2$ then its terminal velocity will be-

Name: Video solution 1: In Millikan oil drop experiment a charged drop falls with a terminal velocity V. If an electric field E is applied vertically upwards it moves with terminal velocity 2V in upward direction. If electric field reduces to E/2 then its terminal velocity will be-
Uploaded: 2023-06-06T08:46:48.000Z
Duration: 8 min
Description: Video solution 1: In Millikan oil drop experiment a charged drop falls with a terminal velocity V. If an electric field E is applied vertically upwards it moves with terminal velocity 2V in upward direction. If electric field reduces to E/2 then its terminal velocity will be-

\frac{V}{2}

V

\frac{3 V}{2}

2 V

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Updated on: Jun 6, 2023

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In Millikan oil drop experiment a charged drop falls with a terminal velocity

V

. If an electric field

E

is applied vertically upwards it moves with terminal velocity

2 V

in upward direction. If electric field reduces to

E /2

then its terminal velocity will be-

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

In absence of electric field (i.e.

ε = 0

)

M g = 6 πn v

D_{1} = 6 πn r v ⟶ (1)

In presence of electric field

M g + QE = 6 πn (2 V) ⟶ (2)

When electric field

D

reduced to

E /2

M g + Q (E /2) = 6 πn (V^{1})

D_{3} = 6 πn r (2 V) ⟶ (3)

After solving

(1)

(2)

and

(3)

We get

V^{1} = \frac{3}{2} V

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Question Text	In Millikan oil drop experiment a charged drop falls with a terminal velocity $V$ . If an electric field $E$ is applied vertically upwards it moves with terminal velocity $2 V$ in upward direction. If electric field reduces to $E /2$ then its terminal velocity will be-
Updated On	Jun 6, 2023
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 2
Upvotes	267
Avg. Video Duration	6 min

In Millikan oil drop experiment a charged drop falls with a terminal velocity $V$ . If an electric field $E$ is applied vertically upwards it moves with terminal velocity $2 V$ in upward direction. If electric field reduces to $E /2$ then its terminal velocity will be-

Text solutionVerified

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In Millikan oil drop experiment a charged drop falls with a terminal velocity V. If an electric field E is applied vertically upwards it moves with terminal velocity 2V in upward direction. If electric field reduces to E/2 then its terminal velocity will be-

Text solutionVerified

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In Millikan oil drop experiment a charged drop falls with a terminal velocity $V$ . If an electric field $E$ is applied vertically upwards it moves with terminal velocity $2 V$ in upward direction. If electric field reduces to $E /2$ then its terminal velocity will be-