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In a single slit diffraction experiment first minimum for red

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In a single slit diffraction experiment first minimum for red light ( $660 nm$ ) coincides with first maximum of some other wavelength $λ^{'}$ . The value of $λ^{'}$ is

4400 \overset{˚}{A}

5500 \overset{˚}{A}

4600 \overset{˚}{A}

4000 \overset{˚}{A}

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Updated on: May 5, 2023

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In a single slit diffraction experiment first minimum for red light (

660 nm

) coincides with first maximum of some other wavelength

λ^{'}

. The value of

λ^{'}

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

In a single slit diffraction experiment, position of minima is given by

d sin θ = nλ

So for first minima of red

sin θ = 1 \times (\frac{λ _{R}}{d})

and as first maxima is midway between first and second minima, for wavelength

λ^{'}

,

Its position will be

d sin θ^{'} = \frac{λ ^{'} + 2 λ ^{'}}{2} \Rightarrow sin θ^{'} = \frac{3 λ ^{'}}{2 d}

According to given condition

sin θ = sin θ^{'}

\Rightarrow λ^{'} = \frac{2}{3} λ_{R}

λ^{'} = \frac{2}{3} \times 660 = 440 nm = 4400 \overset{˚}{A}

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Question Text	In a single slit diffraction experiment first minimum for red light ( $660 nm$ ) coincides with first maximum of some other wavelength $λ^{'}$ . The value of $λ^{'}$ is
Updated On	May 5, 2023
Topic	Wave Optics
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 5
Upvotes	626
Avg. Video Duration	9 min

In a single slit diffraction experiment first minimum for red light ( $660 nm$ ) coincides with first maximum of some other wavelength $λ^{'}$ . The value of $λ^{'}$ is

Text solutionVerified

Filo tutor solutions (5)

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In a single slit diffraction experiment first minimum for red light ( 660 nm ) coincides with first maximum of some other wavelength λ′. The value of λ′ is

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In a single slit diffraction experiment first minimum for red light ( $660 nm$ ) coincides with first maximum of some other wavelength $λ^{'}$ . The value of $λ^{'}$ is