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Physics Part-I

Electromagnetic Waves

In a plane electromagnetic wave, the electric field oscillates

Physics Part-I

Class 12

NCERT

Chapter 1: Electric Charges and Fields

47 questions

Chapter 2: Electrostatic Potential and Capacitance

46 questions

Chapter 3: Current Electricity

33 questions

Chapter 4: Moving Charges and Magnetism

41 questions

Chapter 5: Magnetism and Matter

36 questions

Chapter 6: Electromagnetic Induction

28 questions

Chapter 7: Alternating Current

37 questions

Chapter 8: Electromagnetic Waves

20 questions

The terology of different parts of the electromagnetic spectrum is given in the text. Use the formula

E = h ν

(for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation?

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of

2.0 \times 1 0^{10} Hz

and amplitude

48 V m^{- 1}

(a) What is the wavelength of the wave?

(b) What is the amplitude of the oscillating magnetic field?

\times 1 0^{8} m s^{- 1}

]

Suppose that the electric field part of an electromagnetic wave in vacuum is

E = (3.1 N / C) cos [(1.8 r a d / m) y + (5.4 \times 1 0^{6} r a d / s) t] \hat{i}

(a) What is the direction of propagation?
(b) What is the wavelength

λ

?
(c) What is the frequency v?
(d) What is the amplitude of the magnetic field part of the wave?
(e) Write an expression for the magnetic field part of the wave.

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Solving time: 4 mins

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $2.0 \times 1 0^{10} Hz$ and amplitude $48 V m^{- 1}$ .
(a) What is the wavelength of the wave?
(b) What is the amplitude of the oscillating magnetic field?
(c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 $\times 1 0^{8} m s^{- 1}$ ]

Name: Video solution 1: [Solved] In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0×1010Hz and amplitude 48Vm−1.(a) What is the wavelength of the wave?(b) What is the amplitude of the oscillating magnetic field?(c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 ×108ms−1] - Physics Part-I
Uploaded: 2022-08-01T05:08:05.000Z
Duration: 8 min
Description: Video solution 1: [Solved] In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0×1010Hz and amplitude 48Vm−1.(a) What is the wavelength of the wave?(b) What is the amplitude of the oscillating magnetic field?(c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 ×108ms−1] - Physics Part-I

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Updated on: Aug 1, 2022

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Physics Part-I (NCERT)

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Michael Discussed

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of

2.0 \times 1 0^{10} Hz

and amplitude

48 V m^{- 1}

(a) What is the wavelength of the wave?

(b) What is the amplitude of the oscillating magnetic field?

\times 1 0^{8} m s^{- 1}

]

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

(a)

The wavelength is given by

λ = \frac{c}{v} = \frac{3 \times 1 0 ^{8}}{2 \times 1 0 ^{10}} = 1.5 \times 1 0^{- 2} m

(b)

B_{o} = E_{o} / c = 1.6 \times 1 0^{- 7} T

(c)

Energy density due to the electric field,

E_{E} = \frac{1}{2} ϵ_{o} E^{2}

Energy density due to the magnetic field,

E_{B} = \frac{1}{2} B^{2} / μ_{o}

also,

c = \frac{1}{ϵ _{0} μ _{o}}

on solving above equations,

E_{E} = E_{B}

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Practice more questions from Physics Part-I (NCERT)

The terology of different parts of the electromagnetic spectrum is given in the text. Use the formula

E = h ν

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of

2.0 \times 1 0^{10} Hz

and amplitude

48 V m^{- 1}

(a) What is the wavelength of the wave?

(b) What is the amplitude of the oscillating magnetic field?

\times 1 0^{8} m s^{- 1}

]

Suppose that the electric field part of an electromagnetic wave in vacuum is

E = (3.1 N / C) cos [(1.8 r a d / m) y + (5.4 \times 1 0^{6} r a d / s) t] \hat{i}

(a) What is the direction of propagation?
(b) What is the wavelength

λ

?
(c) What is the frequency v?
(d) What is the amplitude of the magnetic field part of the wave?
(e) Write an expression for the magnetic field part of the wave.

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Question Text	In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $2.0 \times 1 0^{10} Hz$ and amplitude $48 V m^{- 1}$ . (a) What is the wavelength of the wave? (b) What is the amplitude of the oscillating magnetic field? (c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 $\times 1 0^{8} m s^{- 1}$ ]
Updated On	Aug 1, 2022
Topic	Electromagnetic Waves
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 2
Upvotes	208
Avg. Video Duration	6 min

Text solutionVerified

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