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If the nuclear radius of { }^{27} {Al} is 3.6 Fermi, the appro

Question

Medium

Solving time: 3 mins

If the nuclear radius of $^{27} Al$ is $3.6$ Fermi, the approximate nuclear radius of $^{64} Cu$ in Fermi is :

2.4

1.2

4.8

3.6

Views: 6,000 students

Updated on: Apr 15, 2023

Found 6 tutors discussing this question

Noah Discussed

If the nuclear radius of

^{27} Al

3.6

Fermi, the approximate nuclear radius of

^{64} Cu

in Fermi is :

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

The radius of the nuclears is directly proportional to cube root of atomic number i.e.

R \propto A^{1/3}

\Rightarrow R = R_{0} A^{1/3}

, where

R_{0}

is a constant of proportionality

\frac{R _{2}}{R _{1}} = (\frac{A _{2}}{A _{1}})^{1/3} (\frac{64}{27})^{1/3} = \frac{4}{3}

where

R_{1} =

the radius of

27 Al

, and

A_{1} =

Atomic mass number of

A l

R_{2} =

the radius of

^{64} Cu

and

A_{2} =

Atomic mass number of Cu

R_{2} = 3.6 \times \frac{4}{3} = 4.8

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Question Text	If the nuclear radius of $^{27} Al$ is $3.6$ Fermi, the approximate nuclear radius of $^{64} Cu$ in Fermi is :
Updated On	Apr 15, 2023
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 7
Upvotes	811
Avg. Video Duration	4 min

If the nuclear radius of $^{27} Al$ is $3.6$ Fermi, the approximate nuclear radius of $^{64} Cu$ in Fermi is :

Text solutionVerified

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If the nuclear radius of $^{27} Al$ is $3.6$ Fermi, the approximate nuclear radius of $^{64} Cu$ in Fermi is :