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If nuclei of a radioactive element is produced at constant rate α and they decays with decay constantλ. At t=0, number of nuclei is zero than the number of nuclei at time t is



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[a] dNdt=α−λN ∫N0dNα−λN=∫t0dt Solving N=αλ(1−e−λt).
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Question Text | If nuclei of a radioactive element is produced at constant rate α and they decays with decay constantλ. At t=0, number of nuclei is zero than the number of nuclei at time t is |
Answer Type | Text solution:1 |
Upvotes | 150 |