If ΔHvap of pure water at 100∘C is 40.627kJmol−1. The value of ΔSvap is

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If {H}_{{{vap}}} of pure water at {100}^{{}}{C} is {40.627}{k}

Question

If $Δ H_{vap}$ of pure water at $100^{\circ} C$ is $40.627 k J m o l^{- 1} .$ The value of $Δ S_{vap}$ is

10.8 91 k J m o l^{- 1}

108.91 J k^{- 1} m o l^{- 1}

606.27 J K^{- 1} m o l^{- 1}

808.27 J K^{- 1} m o l^{- 1}

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Δ H_{vap}

of pure water at

100^{\circ} C

40.627 k J m o l^{- 1} .

The value of

Δ S_{vap}

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Question Text	If $Δ H_{vap}$ of pure water at $100^{\circ} C$ is $40.627 k J m o l^{- 1} .$ The value of $Δ S_{vap}$ is
Answer Type	Video solution: 1
Upvotes	150