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If 200 {MeV} energy is released in the fission of a single {U}

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If $200 MeV$ energy is released in the fission of a single $U^{235}$ nucleus, the number of fissions required per second to produce 1 kilowatt power is $K \times 1 0^{13}$ . Find the value of $K$ .(Given $1 eV = 1.6 \times 1 0^{- 19} J$ )

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Updated on: Sep 7, 2022

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200 MeV

energy is released in the fission of a single

U^{235}

nucleus, the number of fissions required per second to produce 1 kilowatt power is

K \times 1 0^{13}

. Find the value of

K

.(Given

1 eV = 1.6 \times 1 0^{- 19} J

)

7 mins ago

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7 mins ago

Text solutionVerified

Power is given by

P = n (\frac{E}{t}) \Rightarrow 1000 = \frac{n \times 200 \times 1 0 ^{6} \times 1.6 \times 1 0 ^{- 19}}{t}

\Rightarrow \frac{n}{t} = 3.125 \times 1 0^{13}

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Question Text	If $200 MeV$ energy is released in the fission of a single $U^{235}$ nucleus, the number of fissions required per second to produce 1 kilowatt power is $K \times 1 0^{13}$ . Find the value of $K$ .(Given $1 eV = 1.6 \times 1 0^{- 19} J$ )
Updated On	Sep 7, 2022
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 15
Upvotes	1534
Avg. Video Duration	5 min

If $200 MeV$ energy is released in the fission of a single $U^{235}$ nucleus, the number of fissions required per second to produce 1 kilowatt power is $K \times 1 0^{13}$ . Find the value of $K$ .(Given $1 eV = 1.6 \times 1 0^{- 19} J$ )

Text solutionVerified

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If $200 MeV$ energy is released in the fission of a single $U^{235}$ nucleus, the number of fissions required per second to produce 1 kilowatt power is $K \times 1 0^{13}$ . Find the value of $K$ .(Given $1 eV = 1.6 \times 1 0^{- 19} J$ )