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Gravitational force of attraction

Four particle of mass M , move along a circle of radius R unde

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Four particle of mass $M$ , move along a circle of radius $R$ under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is:

\frac{1}{2} \frac{GM}{R ( 2 2 + 1 )}

\frac{1}{2} \frac{GM}{R} (22 - 1)

\frac{1}{2} \frac{GM}{R} (22 + 1)

\frac{GM}{R}

Views: 6,123 students

Updated on: Apr 23, 2023

Exam:

JEE Mains 2021 Sep 1 Shift 2

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Four particle of mass

M

, move along a circle of radius

R

under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is:

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Text solutionVerified

F_{net} = F_{1} + 2 F_{2} cos 4 5^{\circ} = \frac{G M ^{2}}{( 2 R ) ^{2}} + 2 \times \frac{G M ^{2}}{( 2 R ) ^{2}} \times \frac{1}{2} = \frac{G M ^{2}}{4 R ^{2}} + \frac{G M ^{2}}{2 R ^{2}} = \frac{( 4 + 2 ) GM ^{2}}{4 2 R ^{2}} Now F_{C} = F_{net} \frac{M V ^{2}}{R} = \frac{( 4 + 2 ) GM ^{2}}{4 2 R ^{2}} V = \frac{( 4 + 2 )}{4 2} \frac{GM}{R}

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Question Text	Four particle of mass $M$ , move along a circle of radius $R$ under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is:
Updated On	Apr 23, 2023
Topic	Gravitation
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 14
Upvotes	1479
Avg. Video Duration	7 min

Four particle of mass $M$ , move along a circle of radius $R$ under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is:

Text solutionVerified

Filo tutor solutions (14)

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Four particle of mass M , move along a circle of radius R under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is:

Text solutionVerified

Filo tutor solutions (14)

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Four particle of mass $M$ , move along a circle of radius $R$ under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is: