Force acting on a particle changes with time as F=F0(1−t0t) where F0 and t0 are constants. Find average force on the particle in the interval 0≤t≤t0.

Average value =b−a1∫abf(x)dxF(t)=F0(1−t0t) and a=0,b=t0Average Force =2Fo

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Force acting on a particle changes with time as F=F_{0}(1-{t}{

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Force acting on a particle changes with time as $F = F_{0} (1 - \frac{t}{t _{0}})$ where $F_{0}$ and $t_{0}$ are constants. Find average force on the particle in the interval $0 \leq t \leq t_{0}$ .

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Physics for JEE Main and Advanced Mechanics 1 (McGraw Hill)

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Harper Discussed

Force acting on a particle changes with time as

F = F_{0} (1 - \frac{t}{t _{0}})

where

F_{0}

and

t_{0}

are constants. Find average force on the particle in the interval

0 \leq t \leq t_{0}

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

Average value

= \frac{1}{b - a} \int_{a}^{b} f (x) d x

F (t) = F_{0} (1 - \frac{t}{t _{0}})

and

a = 0, b = t_{0}

Average Force

= \frac{F _{o}}{2}

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Question Text	Force acting on a particle changes with time as $F = F_{0} (1 - \frac{t}{t _{0}})$ where $F_{0}$ and $t_{0}$ are constants. Find average force on the particle in the interval $0 \leq t \leq t_{0}$ .
Topic	Physical World
Subject	Physics
Class	Class 11
Answer Type	Text solution:1
Upvotes	111

Force acting on a particle changes with time as $F = F_{0} (1 - \frac{t}{t _{0}})$ where $F_{0}$ and $t_{0}$ are constants. Find average force on the particle in the interval $0 \leq t \leq t_{0}$ .

Text solutionVerified

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Force acting on a particle changes with time as $F = F_{0} (1 - \frac{t}{t _{0}})$ where $F_{0}$ and $t_{0}$ are constants. Find average force on the particle in the interval $0 \leq t \leq t_{0}$ .