For photo - electric effect with incident photo wavelength $\lambda$ the stopping is $V_0$ identify the correct variation(s) of $V_0$ with $\lambda \text{and}1/\lambda$

Answer: A::CSolution: we know that $\frac{hC}{\lambda }W=e{V}_0\Rightarrow \frac{hc}{e\lambda }-\frac{W}{€}=V_0$
for $V_{0}vesos\frac{1}{\lambda }$ we get a straight line with negative slop and positive intercap
for $V_{0}vesus\lambda$ , we get a hydrogen . As with decrease $V_0$ increases
(a) and (c ) is correct option