Get 2 FREE Instant-Explanations on Filo with code FILOAPP

Excess pressure of one soap bubble is four times that of other

Question

Excess pressure of one soap bubble is four times that of other. Then the ratio of volume of first bubble to second one is:

1:64

64:1

4:1

1:2

Views: 1,132 students

Found 2 tutors discussing this question

William Discussed

Excess pressure of one soap bubble is four times that of other. Then the ratio of volume of first bubble to second one is:

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

Excess pressure =

Δ P = \frac{4 T}{R}

Δ P_{A} = 4Δ P_{B}

So,

\frac{Δ P _{A}}{Δ P _{B}} = 4 = \frac{4 T / R _{A}}{4 T / R _{B}} = \frac{R _{B}}{R _{A}}

Now volume is proportional to

(r a d i u s)^{3}

So,

\frac{V _{A}}{V _{B}} = (\frac{R _{A}}{R _{B}})^{3} = (\frac{1}{4})^{3} = \frac{1}{64}

Was this solution helpful?

150

Report

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our physics tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	Excess pressure of one soap bubble is four times that of other. Then the ratio of volume of first bubble to second one is:
Answer Type	Text solution:1
Upvotes	150