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Due to air a falling body faces a resistive force proportional

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Due to air a falling body faces a resistive force proportional to square of velocity $v$ , consequently its effective downward acceleration is reduced and is given by $a = g - k v^{2}$ where $k = 0.002 m^{- 1}$ . The terminal velocity of the falling body is (in m/s)

Name: Video solution 1: Due to air a falling body faces a resistive force proportional to square of velocity v, consequently its effective downward acceleration is reduced and is given by a=g−kv2 where k=0.002m−1. The terminal velocity of the falling body is (in m/s)
Uploaded: 2023-02-06T10:04:16.000Z
Duration: 15 min
Description: Video solution 1: Due to air a falling body faces a resistive force proportional to square of velocity v, consequently its effective downward acceleration is reduced and is given by a=g−kv2 where k=0.002m−1. The terminal velocity of the falling body is (in m/s)

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Updated on: Feb 6, 2023

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Due to air a falling body faces a resistive force proportional to square of velocity

v

, consequently its effective downward acceleration is reduced and is given by

a = g - k v^{2}

where

k = 0.002 m^{- 1}

. The terminal velocity of the falling body is (in m/s)

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

As velocity increases a will decrease and at some point, it will become zero and velocity become constant that is terminal velocity.
At terminal velocity

g - kv_{ter}^{2} = 0

\Rightarrow v_{ter}^{2} = \frac{g}{k} = \frac{9.8}{0.002} = 4900

\Rightarrow v_{ter} = 70 m s

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Question Text	Due to air a falling body faces a resistive force proportional to square of velocity $v$ , consequently its effective downward acceleration is reduced and is given by $a = g - k v^{2}$ where $k = 0.002 m^{- 1}$ . The terminal velocity of the falling body is (in m/s)
Updated On	Feb 6, 2023
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 2
Upvotes	263
Avg. Video Duration	8 min

Due to air a falling body faces a resistive force proportional to square of velocity $v$ , consequently its effective downward acceleration is reduced and is given by $a = g - k v^{2}$ where $k = 0.002 m^{- 1}$ . The terminal velocity of the falling body is (in m/s)

Text solutionVerified

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Due to air a falling body faces a resistive force proportional to square of velocity v, consequently its effective downward acceleration is reduced and is given by a=g−kv2 where k=0.002m−1. The terminal velocity of the falling body is (in m/s)

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Due to air a falling body faces a resistive force proportional to square of velocity $v$ , consequently its effective downward acceleration is reduced and is given by $a = g - k v^{2}$ where $k = 0.002 m^{- 1}$ . The terminal velocity of the falling body is (in m/s)