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Acceleration due to gravity below and above the surface of earth

Draw g^{} versus d and g^{} versus h graph. Here, ' d ' is dep

Question

Medium

Solving time: 3 mins

Draw $g^{'}$ versus $d$ and $g^{'}$ versus $h$ graph. Here, ' $d$ ' is depth below the surface of earth and $h$ is the height from the surface of earth.

Views: 5,874 students

Book:

Mechanics Volume 2 (DC Pandey)

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Mateo Discussed

Draw

g^{'}

versus

d

and

g^{'}

versus

h

graph. Here, '

d

' is depth below the surface of earth and

h

is the height from the surface of earth.

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

On the surface of earth,

g^{'} = g

At depth '

d

' below the surface of earth,

g^{'} = g (1 - \frac{d}{R})

i.e.

g^{'}

decreases linearly with depth.
Solution Image

At,

d = R, g^{'} = 0

At height

h

above the surface of earth.

g^{'} = \frac{g}{( 1 + \frac{h}{R} ) ^{2}}

With increase in the value of '

h

' value of

g^{'}

decreases but not linearly. At

h \to \infty, g^{'} \to 0

. The correct graph is as shown in Fig.

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Question Text	Draw $g^{'}$ versus $d$ and $g^{'}$ versus $h$ graph. Here, ' $d$ ' is depth below the surface of earth and $h$ is the height from the surface of earth.
Topic	Gravitation
Subject	Physics
Class	Class 11
Answer Type	Text solution:1
Upvotes	119

Draw $g^{'}$ versus $d$ and $g^{'}$ versus $h$ graph. Here, ' $d$ ' is depth below the surface of earth and $h$ is the height from the surface of earth.

Text solutionVerified

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Draw $g^{'}$ versus $d$ and $g^{'}$ versus $h$ graph. Here, ' $d$ ' is depth below the surface of earth and $h$ is the height from the surface of earth.