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Calculate the approximate change in density of water in a lake

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Calculate the approximate change in density of water in a lake at a depth of $400 m$ below the surface. The density of water at the surface is $1030 kg / m^{3}$ and bulk modulus of water is $2 \times 1 0^{9} N / m^{2}$

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Updated on: Feb 6, 2023

Book:

Mechanics Volume 2 (DC Pandey)

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Calculate the approximate change in density of water in a lake at a depth of

400 m

below the surface. The density of water at the surface is

1030 kg / m^{3}

and bulk modulus of water is

2 \times 1 0^{9} N / m^{2}

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

ρ^{'} = \frac{ρ}{1 - \frac{d p}{B}} ∴ Δ ρ = \approx ρ (1 + \frac{d p}{B}) = ρ^{'} - ρ = \frac{ρ ( d p )}{B} \frac{ρ ( ρ g h )}{B} = \frac{( 1030 ) ^{2} \times 9.8 \times 400}{2 \times 1 0 ^{9}} = 2.0 kg / m^{3}

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Question Text	Calculate the approximate change in density of water in a lake at a depth of $400 m$ below the surface. The density of water at the surface is $1030 kg / m^{3}$ and bulk modulus of water is $2 \times 1 0^{9} N / m^{2}$
Updated On	Feb 6, 2023
Topic	Mechanical Properties of Solids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 3
Upvotes	334
Avg. Video Duration	5 min

Calculate the approximate change in density of water in a lake at a depth of $400 m$ below the surface. The density of water at the surface is $1030 kg / m^{3}$ and bulk modulus of water is $2 \times 1 0^{9} N / m^{2}$

Text solutionVerified

Filo tutor solutions (3)

Practice questions from Mechanics Volume 2 (DC Pandey)

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Calculate the approximate change in density of water in a lake at a depth of 400 m below the surface. The density of water at the surface is 1030 kg/m3 and bulk modulus of water is 2×109 N/m2

Text solutionVerified

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Practice questions from Mechanics Volume 2 (DC Pandey)

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Calculate the approximate change in density of water in a lake at a depth of $400 m$ below the surface. The density of water at the surface is $1030 kg / m^{3}$ and bulk modulus of water is $2 \times 1 0^{9} N / m^{2}$