Calculate binding energy of 92U238. Given M(U238)=238.050783amumn=1.008665amu and mp=1.007825amu

801.7MeV

18.7 MeV

0.7 MeV

1801.7 MeV.

Views: 2,047 students

Found 5 tutors discussing this question

Mila Discussed

Calculate binding energy of 92U238. Given M(U238)=238.050783amumn=1.008665amu and mp=1.007825amu

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

[d] Mass defect Δm=[Zmp+(A−Z)mn]−M(U238) =[92×1.007825(238−92)×1.008665]− 238.050783 Δm=1.93421amu BE=1.93421×931.5MeV=1801.7MeV

Was this solution helpful?

151

Report

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our physics tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	Calculate binding energy of 92U238. Given M(U238)=238.050783amumn=1.008665amu and mp=1.007825amu
Answer Type	Text solution:1
Upvotes	151