At 15∘C, a wheel has diameter of 30 cm and inside diameter of a steel rim is 29.9 cm. Coefficient of thermal expansion of steel is 1.2×10−5/oC. To what temperature, the rim must be heated so that it can slip over wheel?

2787∘C

2772∘C

2529∘C

2802∘C

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At 15∘C, a wheel has diameter of 30 cm and inside diameter of a steel rim is 29.9 cm. Coefficient of thermal expansion of steel is 1.2×10−5/oC. To what temperature, the rim must be heated so that it can slip over wheel?

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Text solutionVerified

Rim will slip if its diameter increases to 30 cm. Hence Δl=0.1cm

Δ T = Δ l l \times a = 0.129 .9 \times 1.2 \times 10 - 5 = 2787 o C

Rim to be heated to temperature\displaystyle{2787}+{15}={2802}{o}{C}

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Question Text	At 15∘C, a wheel has diameter of 30 cm and inside diameter of a steel rim is 29.9 cm. Coefficient of thermal expansion of steel is 1.2×10−5/oC. To what temperature, the rim must be heated so that it can slip over wheel?
Answer Type	Text solution:1
Upvotes	152

At 15∘C, a wheel has diameter of 30 cm and inside diameter of a steel rim is 29.9 cm. Coefficient of thermal expansion of steel is 1.2×10−5/oC. To what temperature, the rim must be heated so that it can slip over wheel?

Text solutionVerified

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