An instantaneous displacement of a simple harmonic oscillator is x=Acos(ωt+4π). Its speed will be maximum at

Velocity, v=dtdx=−Aωsin (ωt+π/4)Velocity will be maximum, when ωt+4π =2π⇒ωt=2π−4π=4π⇒t=4ωπ

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An instantaneous displacement of a simple harmonic oscillator

Question

An instantaneous displacement of a simple harmonic oscillator is $x = A cos (ω t + \frac{π}{4})$ . Its speed will be maximum at

\frac{π}{4 ω}

\frac{π}{2 ω}

\frac{π}{ω}

\frac{2 π}{ω}

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An instantaneous displacement of a simple harmonic oscillator is

x = A cos (ω t + \frac{π}{4})

. Its speed will be maximum at

12 mins ago

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12 mins ago

Velocity,

v = \frac{d x}{d t} = - A ω sin (ω t + π /4)

Velocity will be maximum, when

ω t + \frac{π}{4} = \frac{π}{2}

\Rightarrow ω t = \frac{π}{2} - \frac{π}{4} = \frac{π}{4}

\Rightarrow t = \frac{π}{4 ω}

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Question Text	An instantaneous displacement of a simple harmonic oscillator is $x = A cos (ω t + \frac{π}{4})$ . Its speed will be maximum at
Answer Type	Text solution:1
Upvotes	151