An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be

163R

2R16

3R16

4R16

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An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be

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[c] Wave number\displaystyle{1}λ={R}{\left[{1}{n}{21}−{1}{n}{22}\right]}={R}{\left[{14}−{116}\right]}={3}{R}{16}

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Question Text	An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be
Answer Type	Text solution:1
Upvotes	150

An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be

Text solutionVerified

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