A thin plate of large area is placed midway in a gap of height $h$ filled with oil of viscosity and the plate is pulled at a constant velocity $\eta$ is then substituted in the gap, it is found that for the velocity $v$, and the same drag force as previous case the plate is located unsymmetrically in the gap but parallel to the walls. The $\eta$ in terms of distance from nearer wall to the plane $y$ is $\frac{x{\eta }_{0}vA}{h},\frac{4{\eta }_{0}y}{h}\left(1-\frac{y}{h}\right)$. Find the value of x.

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