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Physics Part-I

Laws of motion

A stone of mass 0.25 kg tied to the end of a string is whirled

Physics Part-I

Class 11

NCERT

Chapter 1: Physical World

16 questions

Chapter 2: Units and Measurements

51 questions

Chapter 3: Motion in Straight Line

50 questions

Chapter 4: Motion in a Plane

43 questions

Chapter 5: Laws of motion

52 questions

A batsman deflects a ball by an angle of

9 0^{o}

without changing its initial speed, which is equal to

54 km / h r

. What is the impulse imparted to the ball? (Mass of the ball is

0.15 k g

A stone of mass

0.25 k g

tied to the end of a string is whirled round in a circle of radius

1.5 m

with a speed of

40 re v ./

in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of

200 N

The speed of the stone is increased beyond the maximum permissible value, and the string breaks suddenly, which of the following correctly describes the trajectory of the stone after the string breaks:

(a) the stone moves radially outwards,

(b) the stone flies off tangentially from the instant the string breaks,

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Chapter 6: Work, Energy and Power

41 questions

Chapter 7: System of Particles and Rotational Motion

45 questions

Chapter 8: Gravitation

33 questions

Question

Easy

Solving time: 2 mins

A stone of mass $0.25 k g$ tied to the end of a string is whirled round in a circle of radius $1.5 m$ with a speed of $40 re v ./$ in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of $200 N$ ?

Views: 6,058 students

Updated on: Sep 23, 2023

Book:

Physics Part-I (NCERT)

Found 4 tutors discussing this question

Daniel Discussed

A stone of mass

0.25 k g

tied to the end of a string is whirled round in a circle of radius

1.5 m

with a speed of

40 re v ./

in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of

200 N

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

Mass of the stone,

m = 0.25 k g

Radius of the circle,

r = 1.5 m

Number of revolution per second,

n = 40/60 = 2/3 r p s

Angular velocity,

ω = 2 πn

The centripetal force for the stone is provided by the tension

T

, in the string, i.e.,

T = m ω^{2} r

= 0.25 \times 1.5 \times (2 \times 3.14 \times (2/3))^{2}

= 6.57 N

Maximum tension in the string,

T_{ma x} = 200 N

T_{m} a x = \frac{m v _{ma x}^{2}}{r}

v_{ma x} = (\frac{T _{ma x} r}{m})^{1/2}

= (200 \times 1.5 / 0.25)^{1/2}

= (1200)

^{1/2}

34.64 m / s

Therefore, the maximum speed of the stone is

34.64 m / s

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Practice more questions from Physics Part-I (NCERT)

A batsman deflects a ball by an angle of

9 0^{o}

without changing its initial speed, which is equal to

54 km / h r

. What is the impulse imparted to the ball? (Mass of the ball is

0.15 k g

A stone of mass

0.25 k g

tied to the end of a string is whirled round in a circle of radius

1.5 m

with a speed of

40 re v ./

in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of

200 N

(a) the stone moves radially outwards,

(b) the stone flies off tangentially from the instant the string breaks,

View all

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Question Text	A stone of mass $0.25 k g$ tied to the end of a string is whirled round in a circle of radius $1.5 m$ with a speed of $40 re v ./$ in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of $200 N$ ?
Updated On	Sep 23, 2023
Topic	Laws of motion
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 5
Upvotes	545
Avg. Video Duration	5 min

Text solutionVerified

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